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JEE Main 29-Jan-2024 Shift 1 Solved Paper
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Section:
Physics
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© examsnet.com
Question : 53
Total: 90
A square loop of side
10
cm
and resistance
0.7
Ω
is placed vertically in east-west plane. A uniform magnetic field of
0.20
T
is set up across the plane in north east direction. The magnetic field is decreased to zero in
1
s
at a steady rate. Then, magnitude of induced emf is
√
x
×
10
−
3
V
. The value of
x
is___
[29-Jan-2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
→
A
=
(
0.1
)
2
^
j
→
B
=
0.2
√
2
^
i
+
0.2
√
2
^
j
Magnitude of induced emf
e
=
∆
ϕ
∆
t
=
→
B
⋅
→
A
−
0
1
=
√
2
×
10
−
3
V
© examsnet.com
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