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CBSE Class 12 Chemistry 2013 Solved Paper

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Question : 17 of 30
Marks: +1, -0
Explain the mechanism of the following reaction:2CH3−CH2−OH→413 KH+2 \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{OH} \xrightarrow[413\,\mathrm{K}]{\mathrm{H}^{+}} CH3CH2−O−CH2−CH3\mathrm{CH}_3\mathrm{CH}_2-\mathrm{O}-\mathrm{CH}_2-\mathrm{CH}_3 +H2O+\mathrm{H}_2\mathrm{O}
Solution:  
2CH3CH2OH→C2H5OH.410K (in excess)Heat with H2SO42 \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \xrightarrow[\mathrm{C_2H_5OH.410K}\text{ (in excess)}]{\text{Heat with }\mathrm{H}_2\mathrm{SO}_4} CH3CH2OH\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} ─O∙∙─CH2CH3─\overset{\underset{}{}}{O}{\bullet}{\bullet}─\mathrm{CH}_2\mathrm{CH}_3
Mechanism:
Step I: H2SO4→H++HSO4−\mathrm{H}_2\mathrm{SO}_4 \rightarrow \mathrm{H}^{+}+\mathrm{HSO}_4^{-}
Step II:
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