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CBSE Class 12 Chemistry 2014 Delhi Set 1 Solved Paper

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Question : 9 of 30
Marks: +1, -0
An element with density 11.2 gm cm−311.2\,\mathrm{gm}\,\mathrm{cm}^{-3} forms f.c.c. lattice with edge length 4×10−8 cm4 \times 10^{-8}\,\mathrm{cm}. Calculate the atomic mass of the element. (Given NA=6.022×N_{\mathrm{A}} = 6.022 \times 1023 mol−110^{23}\,\mathrm{mol}^{-1} )
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