CBSE Class 12 Chemistry 2023 Delhi Set 3 Solved Paper

Question : 1 of 13

Marks: +1, -0

SECTION - A

Consider the following standard electrode potential values:

\mathrm{Sn}_{(\mathrm{aq})}^{2+}+2\mathrm{e}^{-}\rightarrow\mathrm{Sn}_{(\mathrm{s})}\mathrm{E}^0

=-0.14\,\mathrm{V}

\mathrm{Fe}^{3+}_{(\mathrm{aq})}+\mathrm{e}^{-}\rightarrow\mathrm{Fe}^{2+}_{(\mathrm{aq})}\mathrm{E}^0

=+0.77\,\mathrm{V}

What is the cell reaction and potential for the spontaneous reaction that occurs?

$2\mathrm{Fe}^{2+}_{(\mathrm{aq})}+\mathrm{Sn}^{2+}_{(\mathrm{aq})}\rightarrow2\mathrm{Fe}^{3+}_{(\mathrm{aq})}$ $+\mathrm{Sn}_{(\mathrm{s})}\mathrm{E}^0=-0.91\,\mathrm{V}$
$2\mathrm{Fe}^{3+}_{(\mathrm{aq})}+\mathrm{Sn}_{(\mathrm{s})}\rightarrow2\mathrm{Fe}^{2+}_{(\mathrm{aq})}$ $+\mathrm{Sn}^{2+}_{(\mathrm{aq})}\mathrm{E}^{\circ}=+0.94\,\mathrm{V}$
$2\mathrm{Fe}^{2+}_{(\mathrm{aq})}+\mathrm{Sn}^{2+}_{(\mathrm{aq})}\rightarrow2\mathrm{Fe}^{3+}_{(\mathrm{aq})}$ $+\mathrm{Sn}_{(\mathrm{s})}\mathrm{E}^0=+0.91\,\mathrm{V}$
$2\mathrm{Fe}^{3+}_{(\mathrm{aq})}+\mathrm{Sn}_{(\mathrm{s})}\rightarrow2\mathrm{Fe}^{2+}_{(\mathrm{aq})}$ $+\mathrm{Sn}^{2+}_{(\mathrm{aq})}\mathrm{E}^{\circ}=+1.68\,\mathrm{V}$

Solution: 👈: Video Solution

E^{\circ}=E_C-E_a

=0.77-(-0.14)=+0.94\,\mathrm{V}

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