An electric dipole of length 2{ cm} , when ...

CBSE Class 12 Physics 2014 Delhi Set 3 Paper

Question : 4 of 8

Marks: +1, -0

An electric dipole of length

2\text{ cm}

, when placed with its axis making an angle of

60^{\circ}

with a uniform electric field, experiences torque of

6\sqrt{3}\text{ Nm}

. Calculate the potential energy of the dipole, if it has a charge of

\pm 2n\text{ C}

Solution:

\tau = pE \sin\theta

6\sqrt{3}=pE \sin\theta

pE\frac{\sqrt{3}}{2}=6\sqrt{3}

So,

pE=12

Potential energy of the dipole

=-pE\cos\theta

U=-pE\cos 60^{\circ}

U=-12\times 0.5

U=-6\text{ J}

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