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CBSE Class 10 Math 2023 All Sets Solved Paper

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Question : 12 of 20
Marks: +1, -0
If ∆ PQR ∼ ∆ ABC, PQ = 6 cm, AB = 8 cm, and perimeter of ∆ ABC is 36 cm, then perimeter of ∆ PQR is
Solution:  
Let perimeter of ∆ PQR be x cm.
Since triangles are similar,
∴   PQAB=  Perimeter of△PQRPerimeter of△ABC\; \frac{PQ}{AB} = \; \frac{\text{Perimeter of} \triangle PQR}{\text{Perimeter of} \triangle ABC}
⇒  68=  x36\Rightarrow \; \frac{6}{8} = \; \frac{x}{36}
⇒x=  6×368\Rightarrow x = \; \frac{6 \times 36}{8}
⇒x=27.\Rightarrow x = 27.
∴ Perimeter of ∆ PQR = 27 cm.
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