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CBSE Class 10 Math 2023 All Sets Solved Paper

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Question : 18 of 20
Marks: +1, -0
(cos4Asin4A)(\cos^4 A - \sin^4 A) on simplification, gives
Solution:  
cos4Asin4A\cos^4 A - \sin^4 A
=(cos2Asin2A)(cos2A+sin2A)=(\cos^2 A - \sin^2 A)(\cos^2 A+\sin^2 A)
=(cos2Asin2A)1=(\cos^2 A - \sin^2 A)\cdot 1
=cos2A(1cos2A)=\cos^2 A -(1-\cos^2 A)
=2cos2A1=2\cos^2 A -1
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