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CBSE Class 10 Math 2023 Delhi Set-3 Solved Paper

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SECTION - D
Section-D consists of Long Answer (LA) type of questions of 5 marks each.
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Question : 10 of 11
Marks: +1, -0
(A) In a △PQR,N\triangle PQR, N is a point on PRPR, such that QN⊥PRQN \perp PR. If PN×NR=QN2PN \times NR = QN^2, prove that ∠PQR=90∘\angle PQR = 90^{\circ}
OR
(B) In the given figure, △ABC\triangle ABC and △DBC\triangle DBC are on the same base BCBC. If ADAD intersects BCBC at O. Proved that   ar(△ABC)ar(△DBC)=  AODO\; \frac{\text{ar}(\triangle ABC)}{\text{ar}(\triangle DBC)} = \; \frac{AO}{DO}
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