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CBSE Class 10 Math 2024 All India Set 1 Solved Paper

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Question : 4 of 20
Marks: +1, -0
If sin A = cos A, then   1−tan⁡A1+tan⁡A\; \frac{1-\tan A}{1+\tan A} is equal to
Solution:  
Given:-
sin A = cos A
  sin⁡Acos⁡A=1\; \frac{\sin A}{\cos A} = 1
∴tan⁡A=1[∵sin⁡Acos⁡A=tan⁡a]\therefore \tan A = 1 \qquad \left[ \because \frac{\sin A}{\cos A} = \tan a \right]
then,
  1−tan⁡A1+tan⁡A\; \frac{1-\tan A}{1+\tan A}
=  1−11+1= \; \frac{1-1}{1+1}
=  02= \; \frac{0}{2}
= 0
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