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CBSE Class 10 Science 2015 Term I Set 1

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Question : 7 of 36
Marks: +1, -0
Name the substance oxidised and the substance reduced, and also identify the oxidising agent and reducing agents in the following reaction :
(a) 3 MnO2+4 Al→3 Mn+2 Al2O33\,\mathrm{MnO}_2+4\,\mathrm{Al}\rightarrow3\,\mathrm{Mn}+2\,\mathrm{Al}_2\mathrm{O}_3
(b) Fe2O3+3 CO→2 Fe+3 CO2\mathrm{Fe}_2\mathrm{O}_3+3\,\mathrm{CO}\rightarrow2\,\mathrm{Fe}+3\,\mathrm{CO}_2
(c) SO2+2 H2S→3 S+2 H2O\mathrm{SO}_2+2\,\mathrm{H}_2\mathrm{S}\rightarrow3\,\mathrm{S}+2\,\mathrm{H}_2\mathrm{O}
Solution:  
Substance oxidised =Al= \mathrm{Al}
Substance reduced =MnO2= \mathrm{MnO}_2
Oxidising agent =MnO2= \mathrm{MnO}_2
Reducing agent =Al= \mathrm{Al}
Substance oxidised =CO= \mathrm{CO}
Substance reduced =Fe2O3= \mathrm{Fe}_2\mathrm{O}_3
Oxidising agent =Fe2O3= \mathrm{Fe}_2\mathrm{O}_3
Reducing agent =CO= \mathrm{CO}
Substance oxidised =H2S= \mathrm{H}_2\mathrm{S}
Substance reduced =SO2= \mathrm{SO}_2
Oxidising agent =SO2= \mathrm{SO}_2
Reducing agent =H2S= \mathrm{H}_2\mathrm{S}
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