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Question : 1
Total: 12
Write the molecular formula of the 2 nd and 3 rd member of the homologous series where the first member is ethyne.
Solution:
(i) CH 3 C ≡ CH (propyne), n = 3
(ii)CH 3 CH 2 C ≡ CH (Butyne), n = 4
(ii)
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