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CBSE Class 10 Science 2017 Outside Delhi Term II Set 2 Paper

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Question : 8 of 12
Marks: +1, -0
Explain esterification reaction with the help of a chemical equation. Describe an activity to show esterification.
Solution:  
The reaction of carboxylic acid with alcohol forms an ester. This process of formation of ester is called esterification.
CH3COOH  +  CH3CH2OH  ightarrow  CH3COOCH2CH3+H2O\mathrm{CH}_3\mathrm{COOH}\;+\;\mathrm{CH}_3\mathrm{CH}_2\mathrm{OH}\; ightarrow\;\mathrm{CH}_3\mathrm{COOCH}_2\mathrm{CH}_3+\mathrm{H}_2\mathrm{O}
Activity :
(i) Take 1 ml1\ \mathrm{ml} of ethanol and 1 ml1\ \mathrm{ml} of glacial acetic acid in a boiling tube and mix the contents well.
(ii) Add few drops of conc. H2SO4\mathrm{H}_2\mathrm{SO}_4 to it.
(iii) Warm the contents on a water bath for a few minutes.
(iv) Now pour the solution in a beaker containing 20−50 mL20-50\ \mathrm{mL} of water.
(v) A sweet fruity smell indicating formation of an ester is observed.
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