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CBSE Class 10 Science 2023 Delhi Set 1

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Question : 1 of 39
Marks: +1, -0
When sodium bicarbonate reacts with dilute hydrochloric acid, the gas evolved is:
Solution:  
Test tube B :
NaHCO3(s)+HCl(aq)→NaCl(aq)+H2O(l)+CO2(g)\mathrm{NaHCO}_3\text{(s)} + \mathrm{HCl}\text{(aq)} \rightarrow \mathrm{NaCl}\text{(aq)} + \mathrm{H}_2\mathrm{O}\text{(l)} + \mathrm{CO}_2\text{(g)}
On passing the carbon dioxide gas evolved through lime water.
Ca(OH)2(aq)(Lime water)+CO2(g)→CaCO3(s)+H2O(l)(White precipitate)\underset{\text{(Lime water)}}{\mathrm{Ca}(\mathrm{OH})_2\text{(aq)}} + \mathrm{CO}_2\text{(g)} \rightarrow \underset{\text{(White precipitate)}}{\mathrm{CaCO}_3\text{(s)} + \mathrm{H}_2\mathrm{O}\text{(l)}}
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