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CBSE Class 10 Science 2023 Delhi Set 3
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Question : 10 of 10
Marks:
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(A) Write the chemical equation for the following: (i) Combustion of methane (ii) Oxidation of ethanol (iii) Hydrogenation of ethene (iv) Esterification Reaction (v) Saponification Reaction OR (B) (i) Draw two structural isomers of butane. (ii) Draw the structures of propanol and propanone. (iii) Name the third homologue of:(a) alcohols(b) aldehydes (iv) Name the following:
(v) Show the covalent bond formation in nitrogen molecule.

Solution:
(A) (i) Combustion of methane:(ii) Oxidation of ethanol:(iii) Hydrogenation of ethene:(iv) Esterification reaction: Carboxylic acid + Alcohol Ester + WaterFor example:(v) Saponification reaction:Ester Salt of carboxylic acid + AlcoholFor example:
(iii) (a) The third homologue of alcohols is propanol, with the chemical formula . It has a straight chain of three carbon atoms and a hydroxyl group attached to the second carbon.(b) The third homologue of aldehydes is propanal, with the chemical formula . It has a straight chain of three carbon atoms with a carbonyl group attached to the second carbon.(iv) (a) Benzene(b) 'But-1-ene'
(B) (i) The two isomers of butane, are:


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