Two pea plants, one with round green seeds ...

CBSE Class 10 Science 2026 Solved Paper All Sets

Question : 4 of 20

Marks: +1, -0

Two pea plants, one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds were crossed with each other which produced

F_{1}

progeny that have only round yellow (RrYy) seeds. When

F_{1}

plants are self-pollinated, the

F_{2}

progeny will have which new combination of characters, as compared to the parents:

(i) Round, yellow

(ii) Round, green

(iii) Wrinkled, yellow

(iv) Wrinkled, green

Correct options are:

Solution:

Parents: RRyy (Round green) X rrYY (Wrinkled Yellow)

Gametes: Ry rY

F_1 :

RrYy

Selfing of

F_1:

RrYy (Round yellow) X RrYy (Round yellow)

Gametes: RY, Ry, rY and ry X RY, Ry, rY and ry

F_2:

RRYY, RRYY, RrYY, RrYy (Round yellow)

RRYY, RRyy, RrYy, Rryy (Round yellow)

RrYY, RrYy, RrYy, Rryy, (Round yellow)

rrYY, rrYy, rrYy (Wrinkled yellow)

rryy (Wrinkled green)

Two pea plants, one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce

F_1

progeny that has round, yellow (RrYy) seeds. When

F_1

plants are selfed, the

F_2

progeny will have a new combination of characters, the combination will be round, yellow and wrinkled green.

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