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CBSE Class 10 Standard Math 2025 All Sets Solved Paper

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Question : 10 of 20
Marks: +1, -0
(3+2)2+(3−2)2(\sqrt{3} + 2)^2 + (\sqrt{3} - 2)^2 is a/an\text{a/an}
Solution:  
(3+2)2+(3−2)2(\sqrt{3}+2)^2+(\sqrt{3}-2)^2
=(3)2+22+2×3×2+(3)2+22−2×3×2= (\sqrt{3})^2 + 2^2 + 2 \times \sqrt{3} \times 2 + (\sqrt{3})^2 + 2^2 - 2 \times \sqrt{3} \times 2
=3+4+43+3+4−43= 3+4+4\sqrt{3}+3+4-4\sqrt{3}
= 14
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