Test Index

CBSE Class 10 Standard Math 2026 All Sets Solved Paper

© examsnet.com
Question : 3 of 20
Marks: +1, -0
Arc PQ subtends an angle θ at the centre of the circle with radius 6.3 cm. If PQ⌢\overset{\frown}{PQ} = 11cm then the value of θ is
Solution:  
Given: l = 11 cm, r = 6.3 cm, π≈227\pi \approx \frac{22}{7}.
Length of Arc (l) = θ360∘×2πr\frac{\theta}{360^{\circ}} \times 2 \pi r
11=θ360∘×2×227×6.311 = \frac{\theta}{360^{\circ}} \times 2 \times \frac{22}{7} \times 6.3
11=θ360∘×44×0.911 = \frac{\theta}{360^{\circ}} \times 44 \times 0.9
11=θ360∘×39.611 = \frac{\theta}{360^{\circ}} \times 39.6
1139.6=θ360∘\frac{11}{39.6} = \frac{\theta}{360^{\circ}}
13.6=θ360∘\frac{1}{3.6} = \frac{\theta}{360^{\circ}}
θ=3603.6=100∘\theta = \frac{360}{3.6} = 100^{\circ}
The value of θ is 100∘100^{\circ}.
© examsnet.com
Go to Question:
Prev Question
Next Question