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CBSE Class 10 Standard Math 2026 All Sets Solved Paper
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Question : 8 of 20
Marks:
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-0
PQ is tangent to a circle with centre O. If ∠POR = 65°, then m∠OPR is

Solution:
In ∆ POR,OP = OR (radii).Therefore, ∠OPR = ∠ORP (angles opposite to equal sides).The sum of angles in a triangle is 180°.In ∆ POR∠POR + ∠OPR + ∠ORP = 180°65° + x + x = 180°65° + 2x = 180°2x = 180° − 65°2x = 115°So, m∠OPR = 57.5°
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