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CBSE Class 12 Chemistry 2016 Delhi Set 1 Solved Paper

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Question : 7 of 26
Marks: +1, -0
When chromite ore FeCr2O4\mathrm{FeCr}_2\mathrm{O}_4 is fused with NaOH\mathrm{NaOH} in presence of air, a yellow coloured compound
(A) is obtained which on acidification with dilute sulphuric acid gives a compound (B). Compound
(B) on reaction with KCl\mathrm{KCl} forms a orange coloured crystalline compound (C).
(i) Write the formulae of the compounds (A), (B) and (C).
(ii) Write one use of compound (C).
OR
Complete the following chemical equations:
(i) MnO4+3S2O32+H2O\mathrm{MnO}_4^{-}+3\mathrm{S}_2\mathrm{O}_3^{2-}+\mathrm{H}_2\mathrm{O}\rightarrow ?
(ii) Cr2O72+3Sn2++14H+\mathrm{Cr}_2\mathrm{O}_7^{2-}+3\mathrm{Sn}^{2+}+14\mathrm{H}^{+}\rightarrow ?
Solution:  
(i)   4FeCr2O4+16NaOH+7O2\;4\mathrm{FeCr}_2\mathrm{O}_4+16\mathrm{NaOH}+7\mathrm{O}_2\rightarrow 8Na2CrO4[A]+  2Fe2O3+8H2O8\mathrm{Na}_2\mathrm{CrO}_4[\mathrm{A}]+\;2\mathrm{Fe}_2\mathrm{O}_3+8\mathrm{H}_2\mathrm{O}
  Na2Cr2O7[B]+2KClK2Cr2O7[C]+2NaCl\;\mathrm{Na}_2\mathrm{Cr}_2\mathrm{O}_7[\mathrm{B}]+2\mathrm{KCl}\rightarrow\mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7[\mathrm{C}]+2\mathrm{NaCl}
  A: Na2CrO4 B: Na2Cr2O7 C: K2Cr2O7\;\mathrm{A}:\ \mathrm{Na}_2\mathrm{CrO}_4\ \mathrm{B}:\ \mathrm{Na}_2\mathrm{Cr}_2\mathrm{O}_7\ \mathrm{C}:\ \mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7
(ii) Use of K2Cr2O7(C)\mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7(\mathrm{C}) : It is used as a strong oxidizing agent in industries.
OR
(i) 8MnO4+3S2O32+H2O8MnO28\mathrm{MnO}_4^{-}+3\mathrm{S}_2\mathrm{O}_3^{2-}+\mathrm{H}_2\mathrm{O}\rightarrow8\mathrm{MnO}_2 +6SO42+2OH+6\mathrm{SO}_4^{2-}+2\mathrm{OH}^{-}
(ii) Cr2O72+3Sn2++14H+2Cr3+\mathrm{Cr}_2\mathrm{O}_7^{2-}+3\mathrm{Sn}^{2+}+14\mathrm{H}^{+}\rightarrow2\mathrm{Cr}^{3+} +7H2O+3Sn4++7\mathrm{H}_2\mathrm{O}+3\mathrm{Sn}^{4+}
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