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CBSE Class 12 Chemistry 2019 Delhi Set 1 Solved Paper

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Question : 18 of 27
Marks: +1, -0
Give the reasons for following:
(i) Transition elements and their compounds act as catalysts.
(ii) EE^{\circ} value for Mn2+Mn\frac{\mathrm{Mn}^{2+}}{\mathrm{Mn}} is negative whereas for Cu2+Cu\frac{\mathrm{Cu}^{2+}}{\mathrm{Cu}} is positive.
(iii) Actinoids show irregularities in their electronic configuration.
Solution:  
(i) Transition metals have the ability to adsorb many other substances on their surface and activate them as a result of chemisorption. Transition metals also exhibit a variety of oxidation states, and can change oxidation states relatively easily. This makes transition metals and their compounds good catalysts.
(ii) EE^{\circ} values are indicative of the stability of the oxidized form of the element. The lower the EE^{\circ} value, more stable the oxidized form of the element. Mn2+\mathrm{Mn}^{2+} with a half filled d-subshell (d5)(d^5) is stable, so Mn\mathrm{Mn} is easily oxidized to Mn2+\mathrm{Mn}^{2+}, making the EE^{\circ} value negative. Cu2+\mathrm{Cu}^{2+} with a partially filled d subshell (d9)(d^9) is not stable, and is relatively easily reduced to element form. This makes its EE^{\circ} value positive.
(iii) The electronic configurations of actinoids show irregularities because the energies of their 5f,6d5 f, 6 d, and 7s7 {s}-orbitals are close to each other. Electrons can easily move between these subshells.
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