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CBSE Class 12 Chemistry 2020 Delhi Set 1 Solved Paper

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Question : 7
Total: 37
How much charge in terms of Faraday is required to reduce one mol of MnO4−to Mn2+ ?
Solution:  
4.825×105C
MnO4−+5e−→
Mn
+7
2+
‌ Charge ‌=5×F=5×96500C =4.825×105C
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