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CBSE Class 12 Chemistry 2022 Term 1 Paper

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Question : 28 of 55
Marks: +1, -0
In the following reaction
CH3CH=CHCH2OHPCC\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{OH} \xrightarrow{\text{PCC}}
the product formed is:
Solution:  
CH3CH=CHCH2OHPCC\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{OH} \xrightarrow{\text{PCC}} CH3CH=CHCOH\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\underset{\mathrm{O}}{\underset{\parallel}{\mathrm{C}}}-\mathrm{H}
Where PCC: Pyridinium chloro oxochromate.
PCC oxidises primary alcohols to aldehydes
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