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CBSE Class 12 Chemistry 2022 Term 2 Delhi Set 2

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Question : 4 of 4
Marks: +1, -0
A primary amine ' AA ' C2H7N\mathrm{C}_2\mathrm{H}_7\mathrm{N} reacts with alkyl halide (C2H51)\left( \mathrm{C}_2\mathrm{H}_5 1 \right) to give secondary amine ' BB '. ' BB ' reacts with C6H5SO2Cl\mathrm{C}_6\mathrm{H}_5\mathrm{SO}_2\mathrm{Cl} to give a solid ' C\mathrm{C} ' which is insoluble in alkali. Identify 'A', 'B', 'C' and write all the chemical reactions involved.
Solution:  
  CH3CH2NH21 Amine (A)+CH3CH2IEthyl iodideCH3CH2NHCH3CH22 Amine(B)\; \underset{1^{\circ}\text{ Amine (A)}}{\mathrm{CH}_3\mathrm{CH}_2\mathrm{NH}_2} + \underset{\text{Ethyl iodide}}{\mathrm{CH}_3\mathrm{CH}_2\mathrm{I}} \rightarrow \underset{2^{\circ}\text{ Amine(B)}}{\mathrm{CH}_3\mathrm{CH}_2\mathrm{NHCH}_3\mathrm{CH}_2}
  +C6H5SO2ClN, N-diethyl benzeneC6H5SO2N2(C2H5)sulphonamide (C)\; + \underset{\text{N, N-diethyl benzene}}{\mathrm{C}_6\mathrm{H}_5\mathrm{SO}_2\mathrm{Cl}} \rightarrow \underset{\text{sulphonamide (C)}}{\mathrm{C}_6\mathrm{H}_5\mathrm{SO}_2\mathrm{N}_2(\mathrm{C}_2\mathrm{H}_5)}
  A=  Ethyl amine  \;A=\;\text{Ethyl amine}\;
  B=  Diethyl amine  \;B=\;\text{Diethyl amine}\;
  C=N,N  -diethyl benzene sulphonamide.  \;C=N, N\;\text{-diethyl benzene sulphonamide.}\;
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