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CBSE Class 12 Chemistry 2023 Delhi Set 1 Solved Paper

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Question : 24 of 35
Marks: +1, -0
(a) (i) Draw the zwitter ion structure for sulphanilic acid.
(ii) How can the activating effect of −NH2-\mathrm{NH}_2 group in aniline be controlled?
OR
(b) (i) Complete the reaction with the main product formed:
(ii) Convert Bromoethane to Propanamine.
Solution:     👈: Video Solution
(i)
(ii) The activating effect of −NH2-\mathrm{NH}_2 group can be reduce by friedal craft (Alkylation & Acetylation) process because nitrogen of aniline required positive charge and hence act as a strong deactivating group.
OR
(b) (i)
(ii) CH3−CH2−BrBromoethane→Sn/KCN\underset{\text{Bromoethane}}{\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{Br}} \xrightarrow{\mathrm{Sn}/\mathrm{KCN}} CH3−CH2−CN\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CN} →2HNa/C2H5−OHCH3−CH2−CH2−NH2Propanamine\xrightarrow[2\mathrm{H}]{\mathrm{Na}/\mathrm{C}_2\mathrm{H}_5-\mathrm{OH}} \underset{\text{Propanamine}}{\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NH}_2}
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