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CBSE Class 12 Chemistry 2023 Delhi Set 1 Solved Paper

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Question : 3 of 35
Marks: +1, -0
A voltaic cell is made by connecting two half cells represented by half equations below:
Sn(aq)2++2e−→Sn(s)E∘\mathrm{Sn}_{(\mathrm{aq})}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn}_{(\mathrm{s})} \mathrm{E}^{\circ} =−0.14 V= -0.14 \text{ V}
Fe3+(aq)+e−→Fe(aq)2+E∘\mathrm{Fe}^{3+}{}_{(\text{aq})}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}_{(\text{aq})}^{2+} \mathrm{E}^{\circ} =+0.77 V= +0.77 \text{ V}
Solution:     👈: Video Solution
Explanation: Sn\mathrm{Sn} is oxidized as it is having -ve value of electrode potential.
E∘=Ec−Ea\mathrm{E}^{\circ} = \mathrm{E}_c - \mathrm{E}_a
=0.77(−0.14)= 0.77(-0.14)
=0.91 V= 0.91 \text{ V}
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