CBSE Class 12 Chemistry 2023 Delhi Set 2 Solved Paper

Question : 1 of 12

Marks: +1, -0

SECTION - A

Consider the following standard electrode potential values:
‌Fe3+‌(aq)+e−→Fe2+‌(aq)Eo =+0.77V
‌MnO4−‌‌(aq) ‌+8H++5e−→Mn2+‌‌(aq) ‌ +4H2O(l)Eo=+
‌1.51V
What is the cell potential for the redox reaction

−2.28V
−0.74V
+0.74V
+2.28V

Solution: 👈: Video Solution

E°=EC−Ea
=1.51−0.77=+0.74V

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