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CBSE Class 12 Chemistry 2023 Outside Delhi Set 1 Solved Paper

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Question : 28 of 35
Marks: +1, -0
A first order reaction is 50% complete in 30 minutes at 300K and in 10 minutes at 320 K. Calculate activation energy (Ea) for the reaction.
[R=8.314 J K1mol1 ]
[Given :log2=0.3010,log3=0.4771, log4=0.6021]
K1 at 27°C or 300 K=0.69330min=0.0231min1
K2 at 47°C or 320K1=0.69310 min=0.0693 min1
Using Arrhenius equation:
log(K2K1)=Ea2.303R (T2T1T1T2)
log(0.06930.0231)=Ea2.303×8.314×103 kj mol1 K1(20300×320)

Ea=43.85 kj mol.
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