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CBSE Class 12 Chemistry 2023 Outside Delhi Set 2 Solved Paper

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Question : 14 of 14
Marks: +1, -0
Write the chemical equation involved in the following:
(a) Kolbe's reaction
(b) Williamson synthesis
Solution:     👈: Video Solution
(a) Kolbe's reaction
(b) Williamson synthesis
R−X+R′Alkyl Halide 1∘−O Na∙∙∙∙SodiumAlakoxide 3∘→{ \mathrm{R}-\mathrm{X}+\mathrm{R}' }_{\text{Alkyl Halide }1^{\circ}} - { \overset{\bullet\bullet}{\underset{\bullet\bullet}{\mathrm{O}\ \mathrm{Na}}} }_{\text{SodiumAlakoxide }3^{\circ}} \rightarrow R−O∙∙∙∙Ether−R′+NaXSodiumHalide{ \mathrm{R} - \overset{\bullet\bullet}{\underset{\bullet\bullet}{\mathrm{O}}} }_{\text{Ether}} - \mathrm{R}' + \underset{\text{SodiumHalide}}{\mathrm{NaX}}
CH3−C∣CH3∣CH3−O−Na++CH3−Br→\mathrm{CH}_3 - { \overset{\mathrm{CH}_3}{\overset{\vert}{\mathrm{C}}} }_{\underset{\mathrm{CH}_3}{\vert}} - \mathrm{O}^{-} \mathrm{Na}^{+} + \mathrm{CH}_3 - \mathrm{Br} \rightarrow CH3−O∙∙∙∙−CCH3∣∣CH3−CH3+NaBr\mathrm{CH}_3 - \overset{\bullet\bullet}{\underset{\bullet\bullet}{\mathrm{O}}} - \overset{\mathrm{CH}_3}{\overset{\vert}{\underset{\vert}{\underset{\mathrm{CH}_3}{\mathrm{C}}}}} - \mathrm{CH}_3 + \mathrm{NaBr}
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