Half-life (t_{1\/2}) of a first order reaction is 1386 s. ...

CBSE Class 12 Chemistry 2026 All Sets Solved Paper

Question : 7 of 16

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Half-life

(t_{1\/2})

of a first order reaction is 1386 s. The value of rate constant is:

Solution:

For a first-order reaction, the formula is:

t_{1\/2} = \;{0.693}/{k}

Given,

t_{1\/2} = 1386s

So,

k =\;{0.693}/{1386}

k = 0.0005 \,s ^{-1}

k = 5.0 × 10 ^{-4} \,s ^{-1}

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