Half-life (t₁/2}) of a first order reaction ...

CBSE Class 12 Chemistry 2026 All Sets Solved Paper

Question : 7 of 16

Marks: +1, -0

Half-life

(t_{1/2})

of a first order reaction is 1386 s. The value of rate constant is:

Solution:

For a first-order reaction, the formula is:

t_{1/2} = \frac{0.693}{k}

Given,

t_{1/2} = 1386s

So,

k = \frac{0.693}{1386}

k = 0.0005\,\mathrm{s}^{-1}

k = 5.0 \times 10^{-4}\,\mathrm{s}^{-1}

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