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CBSE Class 12 Math 2008 Solved Paper

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Question : 3 of 29
Marks: +1, -0
Find the value of x and y if: 2 130x\begin{array}{cc} 1 & 3 \\ 0 & x \end{array} + y012\begin{array}{cc} y & 0 \\ 1 & 2 \end{array} = 5618\begin{array}{cc} 5 & 6 \\ 1 & 8 \end{array}
Solution:  
2 130x\begin{array}{cc} 1 & 3 \\ 0 & x \end{array} + y012\begin{array}{cc} y & 0 \\ 1 & 2 \end{array} = 5618\begin{array}{cc} 5 & 6 \\ 1 & 8 \end{array}
2602x\begin{array}{cc} 2 & 6 \\ 0 & 2x \end{array} + y012\begin{array}{cc} y & 0 \\ 1 & 2 \end{array} = 5618\begin{array}{cc} 5 & 6 \\ 1 & 8 \end{array}
2+y6+00+12x+2\begin{array}{cc} 2+y & 6+0 \\ 0+1 & 2x+2 \end{array} = 5618\begin{array}{cc} 5 & 6 \\ 1 & 8 \end{array}
2+y612(x+1)\begin{array}{cc} 2+y & 6 \\ 1 & 2(x+1) \end{array} = 5618\begin{array}{cc} 5 & 6 \\ 1 & 8 \end{array}
On comparing the corresponding elements of the matrices on both sides, we get:
2 + y = 5 ⇒ y = 3
2(x + 1) = 8 ⇒ x = 3
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