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CBSE Class 12 Math 2008 Solved Paper

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Question : 6 of 29
Marks: +1, -0
Evaluate: ∫
x2
1+x3
 dx
Solution:  
∫
x2
1+x3
 dx
Let 1 + x3 = t
⇒ 0 + 3x2dx = dt
⇒ x2dx =
dt
3
∴ ∫ (
x2
1+x3
) dx = ∫
dt
3
t
=
1
3
‌∫
dt
t
=
1
3
 log |t| + c
=
1
3
 log |1+x3| + c
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