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CBSE Class 12 Math 2009 Solved Paper

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Question : 10 of 29
Marks: +1, -0
Write the value of the determinant |
234
568
6x9x12x
|
Solution:  
Δ = |
234
568
6x9x12x
|
R3 →
1
3x
R3
Δ = 3x |
234
568
234
|
Now , R1 = R3
∴ Δ = 0
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