2x + y – z = 5 Dividing both sides by 5, $\frac{2x}{5}+\frac{y}{5}-\frac{z}{5}$ = 1 ⇒ $\frac{x}{\frac{5}{2}}+\frac{y}{5}+\frac{z}{-5}$ = 1 It is known that the equation of a plane in intercept form is $\frac{x}{a}+\frac{y}{b}+\frac{z}{c}$ = 1, where a, b and c are the intercepts cut off by the plane at x, y, and z-axes respectively. Thus, the intercept cut off by the given plane on the x-axis is $\frac{5}{2}$