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CBSE Class 12 Math 2013 Solved Paper

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Question : 4 of 29
Marks: +1, -0
If |x+1x1x3x+2| = |4113|, then write the value of x.
Solution:  
|x+1x1x3x+2| = |4113|
⇒ (x + 1) (x + 2) - (x - 1) (x - 3) = 12 + 1
x2 + 3x + 2 - x2 + 4x - 3 = 13
⇒ 7x - 1 = 13
⇒ 7x = 14
⇒ x = 2
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