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CBSE Class 12 Math 2018 Solved Paper

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Question : 1
Total: 29
Find the value of tan−1√3−cot−1(−√3)
Solution:  
tan−1√3−cot−1(−√3)
= tan−1√3−[π−cot−1(−√3)] (Since cot−1 (- x) = π - cot−1 (x))
= tan−1√3−π+cot−1(−√3)
tan−1√3+cot−1(−√3) - π
=
π
2
−π (Since tan−1 (x) + cot−1 (x) =
π
2
)
= -
π
2
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