Find the value of \tan^{-1} \sqrt3

CBSE Class 12 Math 2018 Solved Paper

Question : 1 of 29

Marks: +1, -0

Find the value of tan−1√3−cot−1(−√3)

Solution:

tan−1√3−cot−1(−√3)
= tan−1√3−[π−cot−1(−√3)] (Since cot−1 (- x) = π - cot−1 (x))
= tan−1√3−π+cot−1(−√3)
tan−1√3+cot−1(−√3) - π
=

−π (Since tan−1 (x) + cot−1 (x) =

)
= -

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