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CBSE Class 12 Math 2018 Solved Paper

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Question : 15 of 29
Marks: +1, -0
if y = sin (sin x), prove that d2ydx2\frac{d^2y}{dx^2} + tan x dydx\frac{dy}{dx} + y cos2\cos^2 x = 0
Solution:  
y = sin (sin x)
dydx\frac{dy}{dx} = cos (sin x) . cos x
d2ydx2\frac{d^2y}{dx^2} = cos (sin x) - . (- sin x) + cos x . (- si (sin x). cos x)
d2ydx2\frac{d^2y}{dx^2} = - sin x . cos (sin x) - y cos2\cos^2 x
now,
d2ydx2\frac{d^2y}{dx^2} + tan x dydx\frac{dy}{dx} + y cos2\cos^2 x
= - sin x . cos (sin x) - y cos2\cos^2 x + tan x . cos (sin x) . cos x + y cos2\cos^2 x
= - sin x . cos (sin x) - y cos2\cos^2 x + sinxcosx\frac{\sin x}{\cos x} . cos (sin x) . cos x + y cos2\cos^2 x
= 0
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