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CBSE Class 12 Math 2019 All India Set 1 Solved Paper

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Question : 24 of 29
Marks: +1, -0
If A=[1110131−21]A=\begin{bmatrix}1&1&1\\0&1&3\\1&-2&1\end{bmatrix}, find A−1A^{-1}.
Hence, solve the following system of equations :
x+y+z=6x+y+z=6
y+3z=11y+3z=11
   and   x−2y+z=0\;\text{ and }\;x-2y+z=0
OR
Find the inverse of the following matrix, using elementary transformations :
A=[231241372]A=\begin{bmatrix}2&3&1\\2&4&1\\3&7&2\end{bmatrix}
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