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CBSE Class 12 Math 2019 Delhi Set 1 Solved Paper

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Question : 21 of 29
Marks: +1, -0
Solve the differential equation : xdy−ydx=x2+y2dxx dy - y d x = \sqrt{x^2+y^2} d x, given that y=0y = 0 when x=1x = 1.
OR
Solve the differential equation : (1+x2)  dydx+2xy−4x2=0(1+x^2) \; \frac{dy}{dx} + 2xy - 4x^2 = 0, subject to the initial condition y(0)=0y(0) = 0.
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