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CBSE Class 12 Math 2019 Delhi Set 2 Solved Paper

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Question : 9 of 9
Marks: +1, -0
If A=(2−3532−411−2)A = \begin{pmatrix} 2 & -3 & 5 \\ 3 & 2 & -4 \\ 1 & 1 & -2 \end{pmatrix}, then find A−1A^{-1}. Hence solve the following system of equations :
2x−3y+5z=11,3x+2y−4z=−5,x+y−2z=−3.2x-3y+5z=11, 3x+2y-4z=-5, x+y-2z=-3.
OR
Obtain the inverse of the following matrix using elementary operations :
A=(−112123311)A = \begin{pmatrix} -1 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & 1 & 1 \end{pmatrix}
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