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CBSE Class 12 Math 2020 Delhi Set 1 Solved Paper

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Question : 8 of 36
Marks: +1, -0
The graph of the inequality 2x+3y>62 x+3 y>6 is
Given inequality 2x+3y>62 x+3 y>6
3y>6−2x3 y>6-2 x
y>  6−2x3y>\;\frac{6-2x}{3}
Now consider y=  6−2x3y=\;\frac{6-2x}{3} and plot the graph [Ref. image ]]
XX OO 3
YY 2 OO
we used dashed as
y>  6−2x3y>\;\frac{6-2x}{3} as there in no equal to sign
∵y\because y is greater than   6−2x3\;\frac{6-2x}{3} we will shade the upper part [Ref. image 2]
Thus the graph of 2x+3y>62 x+3 y>6 is drawn
Among the option only {B}\{B\} true
half-plane the neither contains origin nor the points of the the line 2x+3y=62 x+3 y=6
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