Evaluate : \sin [\frac{\pi}{3}- \sin ^{-1} (\frac{-1}{2}) ]

CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper

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Question : 5

Total: 11

Evaluate : sin‌[‌

π

3

−sin‌−1(‌

−1

2

)]

Solution:

The value of sin‌(‌

π

3

−sin‌−1(−‌

1

2

))
=sin‌(‌

π

3

−(−‌

π

6

))
=sin‌‌

π

2

=1

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