Evaluate : \sin [\frac{\pi}{3}- \sin ^{-1} (\frac{-1}{2}) ]

CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper

Question : 5 of 11

Marks: +1, -0

Evaluate :

sin \; [\;{π}/{3}- sin \;^{-1} (\;{-1}/{2}) ]

Solution:

The value of

sin \; (\;{π}/{3}- sin \;^{-1} (-\;{1}/{2}) )

= sin \; (\;{π}/{3}- (-\;{π}/{6}) )

= sin \;\;{π}/{2}

=1

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