Concept:The distance of the origin $(0,0,0)$ from the plane $a x+b y+c z+d=0$ is given by $\left| \; \frac{(a)(0)+(b)(0)+(c)(0)+d}{\sqrt{a^2+b^2+c^2}} \right|$Calculation:We know that the distance of the origin $(0,0,0)$ from the plane $a x+b y+c z+d=0$ is given by $\left| \; \frac{(a)(0)+(b)(0)+(c)(0)+d}{\sqrt{a^2+b^2+c^2}} \right|$$\Rightarrow$ The distance of the origin from the plane $2 x+6 y-3 z+7=0$$= \left| \; \frac{(2)(0)+(6)(0)+(-3)(0)+7}{\sqrt{2^2+6^2+(-3)^2}} \right|$$= \left| \; \frac{7}{\sqrt{49}} \right|$$= 1$