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CBSE Class 12 Math 2020 Outside Delhi Set 3 Solved Paper

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Question : 2 of 11
Marks: +1, -0
If A=[a000a000a], then det(adjA) equals
a6
A=[a000a000a]
∴|A|=[a000a000a]=a3≠0
and
n=3
Thus, we have
|adjA|=|A|n−1=(a3)2=a6
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