If {\R}= \{(x, y) ; x, y \in {\Z}, x^2+y^2 \leq 4\} is a ...

CBSE Class 12 Math 2022 Term I Solved Paper

Question : 15

Total: 50

If R={(x,y);x,y∈Z,x2+y2≤4} is a relation in set Z, then domain of R is

{0,1,2}
{−2,−1,0,1,2}
{0,−1,−2}
{−1,0,1}

Solution: 👈: Video Solution

Explanation: Given,
R={(x,y):x,y∈Z,x2+y2≤4}
‌ Since, ‌‌‌begin‌aligned‌y‌=f(x)
y‌=√4−x2‌end‌aligned
‌ For, ‌x=0,±1,±2,⇒y=±2,±√3,0
Since,
Hence, the required domain will be 0±1,±2

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