The principal value of \tan ^{-1} (\tan \frac{9 \pi}{8}) is

CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 19 of 50

Marks: +1, -0

The principal value of tan−1(tan‌

9π

8

) is

‌
π
8
‌
3π
8
−‌
π
8
−‌
3π
8

Solution: 👈: Video Solution

Explanation: tan−1(tan‌

9π

8

)=tan−1(tan(π+‌

π

8

))
=tan−1(tan‌

π

8

)=‌

π

8

‌‌[∵‌

π

8

∈(‌

−π

2

,‌

π

2

)]

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