The principal value of [\tan ^{-1} \sqrt{3}-\cot ...

CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 34

Total: 50

The principal value of [tan−1√3−cot−1(−√3)] is

π
−‌
π
2
0
2√3

Solution: 👈: Video Solution

We have,
tan−1√3−cot−1‌(−√3)
‌=‌

π

3

−(π−‌

π

6

)
‌=tan−1(tan‌

π

3

)−π+cot−1‌cot‌

π

6

‌=‌

π

3

−‌

5π

6

‌=−‌

π

2

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