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CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 34 of 50
Marks: +1, -0
The principal value of [tan−1√3−cot−1(−√3)] is
Solution:     👈: Video Solution
We have,
tan−1√3−cot−1‌(−√3)
‌=‌
π
3
−(π−‌
π
6
)
‌=tan−1(tan‌
π
3
)−π+cot−1‌cot‌
π
6

‌=‌
π
3
−‌
5π
6

‌=−‌
π
2
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