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CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 42 of 50
Marks: +1, -0
The corner points of the feasible region determined by a set of constraints (linear inequalities) are P(0,5)P(0,5), Q(3,5),R(5,0)Q(3,5), R(5,0) and S(4,1)S(4,1) and the objective function is Z=ax+2byZ=a x+2 b y where a,b>0a, b>0. The condition on aa and bb such that the maximum ZZ occurs at QQ and SS is
Explanation: Given, Max. Z=ax+2byZ=a x+2 b y
Max. value of ZZ on Q(3,5)=Q(3,5)= Max. value of ZZ on S(4,1)S(4,1)
⇒  3a+10b  =4a+2b\Rightarrow\; 3 a+10 b\; =4 a+2 b
⇒  a−8b  =0\Rightarrow\; a-8 b\; =0
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