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CBSE Class 12 Math 2022 (Term II) Outside Delhi Set 1 Solved Paper

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Question : 8 of 14
Marks: +1, -0
Find the particular solution of the differential equation x  dydx−y=x2⋅exx \; \frac{dy}{dx} - y = x^2 \cdot e^x, given y(1)=0y(1)=0.
OR
Find the general solution of the differential equation x  dydx=y(log⁡y−log⁡x+1)x \; \frac{dy}{dx} = y(\log y - \log x + 1).
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