Recent studies suggest that roughly $12 \%$ of the world population is left handed. Depending upon the parents, the chances of having a left handed child are as follows :A : When both father and mother are left handed :Chances of left handed child is $24 \%$.B : When father is right handed and mother is left handed :Chances of left handed child is $22 \%$.C : When father is left handed and mother is right handed :Chances of left handed child is $17 \%$.D : When both father and mother are right handed :Chances of left handed child is 9\%.Assuming that $P(A)=P(B)=P(C)=P(D)=\;\frac{1}{4}$ and $L$ denotes the event that child is left handed.Based on the above information, answer the following questions :(i) Find $P(L / C)$(ii) Find $P(\overline{L} / A)$(iii) (a) Find $P(A / L)$ OR (b) Find the probability that a randomly selected child is left handed given that exactly one of the parents is left handed.